C・C++で10進数を2進数に変換する

#include <stdio.h>
int main(void) {
    unsigned number = 13, value = number; int bits[32], count = 0;
    // Store remainders generated from right to left.
    do { bits[count++] = value % 2; value /= 2; } while (value);
    printf("%u = ", number); while (count) printf("%d", bits[--count]); puts("");
}

#include <bitset>
#include <iostream>
#include <string>
int main() {
    unsigned number = 13;
    // Remove leading zeroes from a fixed-width bitset string.
    std::string bits = std::bitset<32>(number).to_string();
    bits.erase(0, bits.find_first_not_of('0'));
    std::cout << number << " = " << bits << '\n';
}